题目：将二维数组中的字符串排序，*characters[] = {"Computer","com.munication","ConsumerElectronics","android","IOS",".text","notepad++","eclipse","code.blocks","VS studio 2015"};

1 #include
     
       2 #include
      
        3  4 char *characters[] = {
   "Computer","com.munication","ConsumerElectronics","android","IOS",".text","notepad++","eclipse","code.blocks","VS studio 2015"}; 5  6 void sort(char *p[], int n)//冒泡排序 7 { 8     char *tmp; 9     int i, j, k;10     for(i = 0; i < (n - 1); ++i)11     {12         k = i;13         for(j = (i + 1); j < n; ++j)14         {15             if(stricmp(p[k], p[j]) > 0)//比较字符串大小的函数stricmp()16             {17                 k = j;18             }19         }20         if(k != i)21         {22             tmp = p[k];23             p[k] = p[i];24             p[i] = tmp;25         }26     }27 }28 29 int main()30 {31     int n = sizeof(characters)/sizeof(characters[0]);//计算characters的行数32     sort(characters, n);//传参要统一characters是指向指针的指针33     int i;34     for(i = 0; i < n; ++i)35     {36         printf("%s\n", characters[i]);37     }38 39     return 0;40 }
      
     

结果如下：